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gm280

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Well I got very similar answers. Does your method hold up for any percentage calculation? I remember chemistry class where we had to do such equations for so many solutions using the solute and solvent. And you couldn't just add in the amounts together because then the ration changes depending on the total volume you were talking about. And I thought there was a interesting formula we used to do it. But that was centuries ago...well a lot of decades anyways... lol Chemistry was not my best subject...electronics was!

If my math is correct, and I am looking at this correctly, you are looking at 752.62 oz (5.88 gal) of gasoline to 15.36 oz of oil.
50/1 = 128x6/X
50/1=768/X
1X=768/50
X=15.36 oz of oil.
768-15.36=752.62 oz of gasoline or 5.8798437 gallons.
@aspeck, after reworking your answer, which I was getting as well, you have not made a 50:1 ration of gas to oil. You now have a 49:1 ration of gas to oil. If you take your 15.36 number (768/50) and multiple it time 49, you will get 752.64 and then add in the 15.36 for the oil, equals 768 which is exactly 6 gallons in ozs. But it isn't a 50:1 ratio anymore, it is now a 49:1 ratio. I fall into that same idea and mindset. And that was why I was asking how to figure it out with a formula to give an exact 50:1 gas to oil ratio. And I am only using the typical 2 cycle mixture for this example. Not that it matters one way or the other. Just interesting.
 

dwco5051

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@aspeck, after reworking your answer, which I was getting as well, you have not made a 50:1 ration of gas to oil. You now have a 49:1 ration of gas to oil. If you take your 15.36 number (768/50) and multiple it time 49, you will get 752.64 and then add in the 15.36 for the oil, equals 768 which is exactly 6 gallons in ozs. But it isn't a 50:1 ratio anymore, it is now a 49:1 ratio. I fall into that same idea and mindset. And that was why I was asking how to figure it out with a formula to give an exact 50:1 gas to oil ratio. And I am only using the typical 2 cycle mixture for this example. Not that it matters one way or the other. Just interesting.
Since I am too old to do all that fancy math (it has been over 60 years since I took differential equations and infinite series in college) I would just mix 16 oz of oil in six gallons of gas, mix it up and then scoop out a pint jar of the mix. No exact measuring of quantities to the 3rd place of a fraction of an ounce. No eyestrain or brain strain and I would have a jar of fire starting fluid when I am burning slashings.
 

gm280

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Since I am too old to do all that fancy math (it has been over 60 years since I took differential equations and infinite series in college) I would just mix 16 oz of oil in six gallons of gas, mix it up and then scoop out a pint jar of the mix. No exact measuring of quantities to the 3rd place of a fraction of an ounce. No eyestrain or brain strain and I would have a jar of fire starting fluid when I am burning slashings.
I surely hope that you knew this was not a serious question about how to mix 2 cycle fuel by any stretch. I was only asking if anyone else remembered their chemistry class and how such ratio solutions were arrived when asked to mix two chemicals to yield a certain percentage amount. I would never ever try to mix my 2 cycle fuel any other way but pour in the 16ozs of TC-W3 oil to the 6 gallon can of gas. I was only asking if anyone knew how to arrive at a precise mixture of 50:1 without going over 6 gallons.
 

dwco5051

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I surely hope that you knew this was not a serious question about how to mix 2 cycle fuel by any stretch. I was only asking if anyone else remembered their chemistry class and how such ratio solutions were arrived when asked to mix two chemicals to yield a certain percentage amount. I would never ever try to mix my 2 cycle fuel any other way but pour in the 16ozs of TC-W3 oil to the 6 gallon can of gas. I was only asking if anyone knew how to arrive at a precise mixture of 50:1 without going over 6 gallons.
I realized that it was a hypothetical question and said how I would do it if I didn't know the math. However the question stuck in my head all afternoon like an old song while I was out in the woods cutting wood. Even to the point that I was thinking if you used the correct proportions would you end up with exactly 6 gallons by volume. When all the various non-polar hydrocarbon molecules that make up both gasoline and oil and are completely miscible would it be like mixing golf balls and marbles where the difference in the sizes of the different molecules would take up less space. Now I will waste some of my remaining hours on this earth looking through some of my old chemistry books along with the math books.
 

64osby

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768 / 51 = 15.0588
50 x 15.0588 = 752.941 oz gas
1 x 15.0588 = 15.0588 oz oil
752.941 + 15.0588 = 767.9998 oz
752.941 / 15.0588 = 50.000066406 or 50 to 1

Might be a drop or two off.
 
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aspeck

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Actually 1 pint in 6 gallons is a 48:1 ration, not a 50:1 ...
 

gm280

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768 / 51 = 15.0588
50 x 15.0588 = 752.941 oz gas
1 x 15.0588 = 15.0588 oz oil
752.941 + 15.0588 = 767.9998 oz
752.941 / 15.0588 = 50.000066406 or 50 to 1

Might be a drop or two off.
I actually did that exact same idea and got the 50:1 mixture. But does that hold up with other mixtures? IDK... Math is such an amazing thing...

I do remember my chemistry class where we had to do such type equations. But I since forgotten the formula you used.
 

dwco5051

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768 / 51 = 15.0588
50 x 15.0588 = 752.941 oz gas
1 x 15.0588 = 15.0588 oz oil
752.941 + 15.0588 = 767.9998 oz
752.941 / 15.0588 = 50.000066406 or 50 to 1

Might be a drop or two off.
Depends on the accuracy of the measuring devices to meter out the quantities of the ingredients. Lets not forget about the importance of significant figures.
 

gm280

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Depends on the accuracy of the measuring devices to meter out the quantities of the ingredients. Lets not forget about the importance of significant figures.
I always figured out that I could take the two solutions, mix them together at the percentages called for and then drained off the overage of the total to get the mixture correct. But for some strange reason, my chemistry teacher didn't like my method... lol
 

WIMUSKY

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You guys are making my brain hurt. And I took all the higher math in HIGH SCHOOL!!!!😂 We need a rocket scientist....😉
 

GA_Boater

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You guys are making my brain hurt. And I took all the higher math in HIGH SCHOOL!!!!😂 We need a rocket scientist....😉

I mix using a 2 stroke oil measuring cup because my oil comes in gallons. This is from a retired rocket scientist. :unsure: :cool:
 

gm280

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WOW, didn't mean to start a brain blow out issue. Was only wondering how to do such equations. On the surface it sounds simple. But when you look at it with the limitations, it isn't so simple anymore. Maybe that is why I didn't like chemistry after all. Don't have such complication with electronics...at least not to me. Pretty simple math equations with electronics.
 

WIMUSKY

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I mix using a 2 stroke oil measuring cup because my oil comes in gallons. This is from a retired rocket scientist. :unsure: :cool:
Who knew! 😳😁
I didn't even look closely at the equations... I glanced at them, I didn't want my head to explode....
 

64osby

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I actually did that exact same idea and got the 50:1 mixture. But does that hold up with other mixtures? IDK... Math is such an amazing thing...

I do remember my chemistry class where we had to do such type equations. But I since forgotten the formula you used.
A 16/1 ratio would be

768 / 17 = 45.1764
45.1764 x 16 = 722.8224 oz gas
45.1764 x 1 = 45.1764 oz oil
722.8224 + 45.1764 = 767.9988
722.8224 / 45.1764 = 16.0 or 16/1

This is not a equation problem, it is a simple division / multiplication problem. You could do a complex 2 variable equation and spend much more time solving it.

When my kids were in school they would have homework that occasionally I would look at, or help with. There were several times where I would help, providing the correct answer. I could not do the process that the teachers were looking for, but always had the correct answer. My kids would provide the correct answer but get a zero grade because they didn't show the "correct" method of getting the answer.

New Math... Male Cow Manure...
 

gm280

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If you think you've had a bad day, maybe you just need something to compare it with...

 

Krazeehorse

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Here's my approach to the math problem. 50:1 is a 2% mixture of oil to fuel, correct? So you want 102% of X to equal 6 gallons or 768 ounces. 768 divided by 1.02 (102%) is 752.94 oz. 768 minus 752.94 equals 15.06 ounces of oil. 15.06 divided by 752.94 equals .02 or 2%.
But I'm probably wrong.
 

gm280

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Here's my approach to the math problem. 50:1 is a 2% mixture of oil to fuel, correct? So you want 102% of X to equal 6 gallons or 768 ounces. 768 divided by 1.02 (102%) is 752.94 oz. 768 minus 752.94 equals 15.06 ounces of oil. 15.06 divided by 752.94 equals .02 or 2%.
But I'm probably wrong.
No, you are not wrong. I only used 2 cycle mixture because this is a boat forum. The ratio could be most any percent of two solutions. We usually simple apply the (in this case) oil to 6 gallons of gas and boat on. But we end up with 6 gallons of gas plus 16ozs of oil for a actual total of 6gallons 16ozs. But if you are working serious chemical solutions, that doesn't get it. But your assessment is correct.
 

DeepCMark58A

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I would just get 5 gallons of mixed gas fill the 2 2 gallon cans and store the rest, not like you won't burn it up next weekend. Lot easier than doing the math.
 
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