If V(2,4) = 11.30V and if *V(1,3) = 12.45V with S1 on and a normal load R3.
V(1,3) = V(1,2)+V(2,4)+V(3,4) eq. 1 (summing voltage in a closed loop)
Then from eq 1 V(1,3) - V(2,4) = V(1,2)+V(3,4) = 12.45 - 11.30 = 1.15V
V(1,2)+V(3,4) = 1.15V
The problem is voltage drops caused by higher then...