SAM,
This is AC wave off a stator..
View attachment 336211
Looks reasonable, but since it's actually
170Vpp (not Vp) migrating equally above and below ground(0V), the DVA referenced to ground would measure 84.4Vp.
Recall a
DVA circuit has a simple rectifier(current only flows one way) with a charge storage cap, thus the cap can only charge up to just the positive peak minus 0.6V(diode junction).
The *meter(set to DC) simply displays highest value the cap charged up to and is holding..... 85Vp - 0.6V = 84.4Vp.
The peak event/s (positive peak and negative peak) in your example are 8.3mS in duration ea. and are well within the flukes "peak min/max" spec of capturing events of 250uS or greater......The fluke set to "peak min/max" would then also display **85Vp.
Additionally regarding the example waveform in #7..........***Vrms = 0.707 * Vp, therefor 85Vp*0.707 = 60.095Vrms, not 120Vrms as incorrectly indicated .
*built in DVA(your example in #2) or external adapter.
** because the fluke uses a precision rectifier, there is no 0.6V diode drop.
***Concider the AC waveformin our houses.....170Vp * 0.707 = 120Vrms, not 240Vrms (see #5 youtube vid)