Explain the 'CD' ignition system, what is 'CD'?

lakedawgs

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I have a 1983 115 hp Johnson. I have seen reference to the different types of Capacitive Discharge ignition systems on these motors but am trying to figure out what I have. It is a model TLCTE. How do I determine which 'CD' ignition I have?
Thanks,
Lakedawgs
 

HighTrim

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Re: Explain the 'CD' ignition system, what is 'CD'?

Your magneto capacitor discharge (ie CD) ignition system consists of five major components. They are the flywheel, stator and charge coil assembly located under the flywheel, timer base and sensor assembly located under flywheel, power pack, ignition coils and spark plugs located at the rear of the motor. These are the main components. A malfunction in your system will result in an engine miss, engine surge, or the engine not running. It is a fairly basic system to troubleshoot, but you will need a few tools such as spark checker set to 7/16 of an inch, ohmmeter, timing light, and a neon test light.

convert.jpg
 

F_R

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Re: Explain the 'CD' ignition system, what is 'CD'?

Good information from hightrim. The question asked in addition to that, "what is CD"

On a conventional old battery/coil ignition system the coil operated on 12 volts from the battery. Breaker points interrupted the 12 volts and each time that happened a high voltage was created in a second winding in the coil, which provided the spark across the spark plug gap.

Enter CD: As you found out there are several ways to accomplish this, but the basic deal is that instead of the coil operating on 12 volts a high voltage is supplied to it--usually around 300 volts. The 300 volts pulse creates a high voltage in the second winding as above. Without getting into electronic theory, lets just say that's better.

So, how do we find a 300 volt supply in a boat with a 12 volt battery? Early systems took the 12 volts and amplified it to 300 volts. That 300 volts was stored in a capacitor until time to fire the plug. Then by some sort of triggering device, the 300 volts was discharged through the coil. Hence "capacitor discharge".

The triggering device changed often but it is either a set of breaker points or some sort of magnetic sensor or light interrupter. Again, lets not get too deep here.

Enter Mag CD: This is what you have. Instead of amplifying 12 volts to 300, these motors generate the 300 volts by using special coils under the flywheel, called "charge coils". From there on, the scheme is the same, store it in a capacitor and discharge it upon a trigger signal from sensor coils also under the flywheel. The big advantage is reduced electronics and the motor runs independently of the battery. You can even rope start it with a completely dead battery.

The CD systems have come a long way from the beginning and the electronics have changed a whole big bunch. They have been pretty much established with the Mag CD similar to yours.

Hope this gives you some basic information without making it complicated.
 

samo_ott

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Re: Explain the 'CD' ignition system, what is 'CD'?

Phew... It sure makes me appreciate the good ole magneto's :) Cheap and easy to fix! Who needs 300 volts!
 

lakedawgs

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Re: Explain the 'CD' ignition system, what is 'CD'?

Really good stuff guys, THANKS!
How do I know which one my 1983 115hp Johnson TLCTE has? CD1 or CD2 or CD3, etc?
THANKS,
Lakedawgs
 

SuperNova

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Re: Explain the 'CD' ignition system, what is 'CD'?

300 volts, huh? Wow, I learn something new on here everyday. I knew that we used capacitors to store the voltage for the coil, but I thought it was just to reduce the rise time of the primary windings, thereby increasing spark power and consistency at high rpm where we have less time to do all the things that need to be done in the primary circuit in order to build enough voltage in the secondary circuit to fire the plug. But I thought we just stored appr. 12 volts I had no idea it actually was 300 volts. Just one question to complete my understanding.....How exactly do we convert the 12 volts into 300 volts? Thanks in advance for you kindly explanation. Oh, yeah. And why 300 volts, specifically?
--
Stan
 

ezeke

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Re: Explain the 'CD' ignition system, what is 'CD'?

CD4 refers to the engine cylinders in your system. Your system has two powerpacks as opposed to one in the earlier CD4 sytems, and has separate ignition coils and charge coils.

As stated earlier, the twelve volts from the battery is only there to turn the starter as far as the ignition system is concerned.
 

F_R

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Re: Explain the 'CD' ignition system, what is 'CD'?

SuperNova, the early systems amplified the 12 volts to 300 volts. It was done within the "amplifier", or "pulse pack" as they were called back them. I have no idea exactly what the internal circuitry was, but I assume some sort of oscillator was involved.

The more modern "mag" CD systems, as I said, do not use the 12volts for ignition at all. On those, the charge coils produce 300VAC directly to the power pack, where it is rectified to DC and stored in the capacitor.
 

Texasmark

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Re: Explain the 'CD' ignition system, what is 'CD'?

As mentioned the advantage of CD is speed and increased firing voltage.....like 40 microsecond rise time rather than 40 millisecond rise time (1000 times faster) sort of thing with conventional systems. Idea there was that the fast rising, usually 40,000 volt (rather than the old 18,000 volt pulse) would not only hit the plug harder, it would fire oil fouled plugs better and it does......before the pulse had time to bleed off through the contaminated insulator.

The 300 volts can easily be created from DC with a pulsed system. A transistor closes and allows (DC) current to flow into a coil and shuts off. The coil voltage rises (inductive kick) and is electronically directed to a capacitor (via a diode rectifier) which fills up to this voltage and holds it.

We now have a source of energy sitting right there in the capacitor ready to go. The ignition trigger pulse comes along and fires the (capacitor dump) switch (transistor/Silicon Controlled Rectifier/Field Effect Transistor....whatever) which dumps it's energy into the ignition coil which steps it up to 40,000 volts causing the plug gap to breakdown and dissipate the energy in the spark......wala ignition.

Benefits here are obviously the higher voltage to the plug gap, and switching speed (which is the speed of the electronic switch as compared to mechanical ignition points), location of the energy source (right there where it's used), and the transformer turns ratio dropping from 1:1500 (12v to 18,000) to 1:133 (300v to 40,000).

HTH

Mark
 

SuperNova

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Re: Explain the 'CD' ignition system, what is 'CD'?

Cool, thanks for the explanation guys! I appreciate anything that increases my understanding.
--
Stan
 
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