Or you could do a "Sheldon" thing. Build a tank big enough to float your boat. Add the boat. Add water until the boat floats. Mark the water level. Now remove the boat and again mark the water level. Now calculate the displacement. Then you begin a spread sheet that includes EVERY detail, every option, every power plant variation and every accessory available and repeat the process. By the time you die you will have covered perhaps 1% of the boats and there would then be at least 1000 more variations that arrived on the scene including electric, hybrid, and hydrogen powered versions. But as was mentioned, just look at the manufacturers specs or go a scale and weigh the old tub.
You guys are overthinking the question: the says he's asked how much HIS boat weighs--not every single similar boat like his!
Only 2 good ways to measure a boat; with a weight scale, or calculating water displacement. As for the tank thing, you won't need to measure the boat's waterline, just fill the tank until it it's full, then remove the boat, then measure how much water is missing.
When I had to crane the SkipperLiner out of the water, crane guy wanted to know how much it weighed, so he knew how much counterweight to bring. This boat's relatively easy to calculate because the hull is dead flat in back with a slight V in front...hull is 12'-6" wide, and at 40' forward where the keel rises up, the keel sits 9" deeper than the sides. The waterline was 10" up in front, 14" up in back, and I tried to factor in the added underwater surface area up front best I could, and it worked out to pretty close to 14", or 1.167', average draft.
SO-- the hull's wet area is 12.5' wide, 40' long, drafts 1.167', and water weighs 62.43 lbs per cubic foot...Doing the math: 40' x 12.5' = 500 sq. feet, x 1.167' draft = 583.5 cubic feet, x 62.43 lbs of water, comes to 36,428 lbs... Crane guy told me his scale said just above 36,000.
Figuring out a typical V hull's displacement would be much trickier for sure, but do-able
