Re: How long is the fish??? Mind boggler.
PS. Damit Google !! LOL
. .. and yes I was being a smart$$ with looking this up
...
Me too, but I had to work out the correct answer after finding out how to solve the problem.
Set up equations from what is given in the problem: H = Head; T = Tail; B = Body
H = 10
T = H + 1/2B
B = H + T
Total Length of the Fish = H + T + B
Substitute between equations.
If we know H = 10 then we can substitute 10 in for H in the second equation.
T = 10 + 1/2B
Now we know what T and H are, so lets substitute that into the third equation and solve for B.
B = H + T
B = 10 + (10 + 1/2B)
B = 20 + 1/2B
Then subtract 1/2B from both sides:
1/2B = 20
Multiply both sides by two:
B = 40
Now we know the value of B and the value of H. Substitute this back into the second equation and solve for T.
T = H + 1/2B
T = 10 + (1/2)40
T = 10 + 20 = 30
Plug all values of H, T, and B into the final equation.
Total length of fish = H + T + B
Total length of fish = 10 + 30 + 40 = 80
